12x^2-124x+12=0

Solution for 12x^2-124x+12=0 equation:

12x^2-124x+12=0

a = 12; b = -124; c = +12;
Δ = b2-4ac
Δ = -1242-4·12·12
Δ = 14800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14800}=\sqrt{400*37}=\sqrt{400}*\sqrt{37}=20\sqrt{37}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-124)-20\sqrt{37}}{2*12}=\frac{124-20\sqrt{37}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-124)+20\sqrt{37}}{2*12}=\frac{124+20\sqrt{37}}{24}
$